20x^2-4x^3/4x

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Solution for 20x^2-4x^3/4x equation: 


x in (-oo:+oo)

20*x^2-(x*((4*x^3)/4)) = 0

20*x^2-x^4 = 0

t_1 = x^2

20*t_1^1-1*t_1^2 = 0

20*t_1-t_1^2 = 0

DELTA = 20^2-(-1*0*4)

DELTA = 400

DELTA > 0

t_1 = (400^(1/2)-20)/(-1*2) or t_1 = (-400^(1/2)-20)/(-1*2)

t_1 = 0 or t_1 = 20

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

t_1 = 20

x^2-20 = 0

1*x^2 = 20 // : 1

x^2 = 20

x^2 = 20 // ^ 1/2

abs(x) = 2*5^(1/2)

x = 2*5^(1/2) or x = -(2*5^(1/2))

x in { 0, 2*5^(1/2), -(2*5^(1/2)) }

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